Assuming that if rain falls on an impervious surface at a constant rate, the resultant runoff from the surface would be equal to the rainfall.
STORM
RUNOFF ESTIMATION
Peak run-off rate depends on.
❖ Type of
precipitation.
❖ Intensity
and duration of rainfall.
❖ Rainfall
distribution.
❖ Soil
moisture.
❖ Direction
of storm/duration/storm frequency.
❖ Climatic
conditions.
•
Shape, size, type of catchment basin.
•
Impermeability factor.
(a) Rational Formula:
❖ Assuming
that if rain falls on an impervious surface at a constant rate, the resultant
runoff from the surface would be equal to the rainfall.
Runoff
rate = Rate of rainfall.
Time
of Concentration:
Period
after which the entire catchment area starts contributing to the runoff in
drains.
Critical
Rainfall Duration:
Maximum
runoff obtained from rain having duration equal to the time of the concentration
Based
on the basic principles, the rational formula was evolved by Fruhling,
Kuichling lioz bied,menuM (S).
Qp
→ Peak rate of runoff in cumecs
K
→ Co-efficient of runoff
A
→ Catchment area in hectares
Pe
→ Critical rainfall intensity (cm/hr).
Co-efficient of Runoff (Impervious
Factor)
❖ The
co-efficient of runoff (k) is the impervious factor of runoff, representing the
ratio of precipitation to runoff.
❖ The
value of k increases as the impreviousness of the area increases.
k
= Ratio of precipitation to runoff
❖ Value
of k varies with the type of surface.
k=1
→ Perfectly impervious surface.
[For
parks, lawns, gardens, k = 0.05 -0.25
Wooden
lands, k = 0.01 -0.20]
Average Impermeability Factor (I)
(k):
A1,A2,
A3 → Area of different surfaces of catchment.
I1,
I2, I3→ Corresponding impermeability factors for
different surfaces.
Intensity
of Rainfall:
❖ It
is expressed in cm/hr.
❖ Automatic
rain gauges measures the rainfall intensity in cm/hr and is plotted on graph.
❖ Readymade
curves, standard depth-duration curves of a particular rain gauge station,
representing different frequencies are provided by Meteorological Department.
❖ The
value of intensity obtained is the rainfall at the rainfall gauge station and
is called as point rainfall intensity.
❖Intensity at any point on catchment area =
Point rainfall intensity × Areal Distribution Factor (dispersion factor)
Time of Concentration:
i)
The Inlet Time (or) Overland Flow Time (or) Time of Equilibrium
The
time taken by water to flow overland from the critical point upto the point
where it enters the drain mouth.
Ti
= Inlet time in hours.
L
= Length of overland flow in kilometers.
H
= Total fall of level (m) from critical point to mouth of drain.
ii) Channel Flow Time/Gutter Flow
Time
Time
of flow from drain channel mouth to considered point.
Time
of concentration,
❖ Intensity
of rainfall during T can be easily obtained from standard intensity duration curves.
❖ In
the absence of standard intensity - duration curves, following formulae is
used.
a) Localities with frequent
rainfall (5 year frequency)
b) Rains with frequency of 10 years
c) Rains with frequency of 1 year
d) Kuichling's formula
(b) Empirical formula for computing
the peak discharge for larger catchment areas
(i) Burkli - Ziegler Formula:
ii) Dicken's Formula:
(North Indian Catchments):
Qp
= CM3/4
M
→ Catchment area in sq.km.
C→
Constant depends on runoff factors (11.5 generally) (Increases for hilly
terrains).
iii) Ryve's Formula:
(South Indian Catchments):
Ci
= 6.8 (Less for flat catchment and more value for hilly areas).
iv) Inglis Formula:
(Fan-Shaped Catchments-Bombay): super di
v) Nawab Jung Bahadur Formula:
(Hyderabad Deccan Catchments):
C2
varies between 48 to 60
M'→
Catchment area in acres.
vi) Dredge (or) Burge's Formula:
L→
Length of drainage basin in Kilometers.
PROBLEMS
1.
The surface on which the rain fall occurs in a district is given below.
The
total area of the district is 36 hectares and the maximum rain intensity is 5
cm/hr.
Determine
i)
Co-efficient of runoff.
ii)
Total runoff for district.
Solution: Runoff ratio for entire
area.
Rational Formula:
2. In the same problem, if the time
of concentration for the area is 30 minutes, find the maximum runoff (if
maximum rain intensity is not given). Also use formula, R=900/(t+60).
Solution:
Time of concentration is given as 30 min.
Rain
intensity = mm/hr (using given formula)
Rational
formula for peak discharge,
Maximum
runoff = Qp = 0.4875 cumecs.
3.
The surface water from airport road is drained to the longitudinal side drain
from across one half of a bituminous pavement suface of total width 7.0 m,
shoulder and adjoining land of width 8.0 m on one side of the drain. On the
other side of the drain, water flows across from reserve land with average turf
and 2% cross slope towards the side drain, the width of this strip of land
being 25 m. The inlet time is 10 min. The runoff coefficients of the pavement,
shoulder and reserve land (turf) are 0.8, 0.25 and 0.35 respectively. The
length of the land parallel to road from where water is expected to flow to
side drain is 400 m.
Estimate
the quantity of runoff flowing in the drain assuming 10 year frequency. The
side drain will pass through clayey soil with allowable velocity of flow as
1.33 m/s.
4.
In problem 1.1, if the density of population is 250 per hectare and the rate of
water supplied per day is 225 Iped. Calculate the quantity of:
a)
Sewage flow for which the sewers of a separate system, should be designed?
b)
Storm water for which the sewers of a partially separate system are designed?
Solution:
i)
Sewage Flow - Separate system.
Population
Density = 250 persons per hectare.
Total
population = 250/hectare × 36 hectare
=
9000.
Water
supply = 225 lpcd
Rate
of water supply = Per capita water demand x Population
=
225 lpcd × 9000
=
202500 l/d
=
2025 m3/d= 2025 24×60×60 m3/s
=
0.0234 m3/s.
Assuming
the sewage discharge is 0.8 times the water supplied.
Rate
of sewage produced (Average Flow) = 0.8 x rate of water supplied
=
0.8 x 0.0234 m3/s.
=
0.0187 m3/s.
Now
assuming the peak flow as three time the average flow
Peak
rate of sewage flow= 3 x Average flow
=
3 x 0.0187 = 0.056 m3/s.
=
0.056 cumecs.
ii) Partially Separate System
In
case of partially separate system, the storm water from roofs and paved yards
of houses will be allowed to enter the sewers.
5. A population of 30,000 is
residing in a town having an area of 60 hectares. If the average co-efficient
to runoff for this area is 0.60 and the time of concentration of the design
rain is 30 min. Calculate the sewage discharge for the sewers in a combined
sewerage system. Assume suitable data.
Solution:
Assuming
average per capita water demand as 120 litres/day/person and that 80% of the
water supply will be reaching the sewers as sanitary sewage.
=
80% of water supplied x Population
Quantity
of sanitary sewage produced per day [80x100]/120pcd x30,000
=2880x103l/d
Average
flow = 2880 m3/d
Quantity of sewage produced per second =2880/24 x 60 x 60 = 0.033m3/2
Assuming
the maximum sewage discharge as 3 time of average sewage discharge
Maximum
Sewage Discharge = 3 x Average Flow
=
3 x 0.033 m3/s.
=
0.1 m3/s.
Water Supply And Wastewater Engineering: Unit IV: Planning And Design Of Sewerage System : Tag: : Formula, Calculation, Solved Example Problems - Storm Runoff Estimation
Water Supply and Wastewater Engineering
CE3303 3rd Semester Civil Dept 2021 Regulation | Tag: 3rd Semester Civil Dept 2021 Regulation