Transforms And Partial Differential Equations: UNIT I: Partial Differential Equations: Examples
R.H.S = xr ys
Example
1.5.12: Solve [D2 - 7DD' + 6D '2] z = xy
Solution:
Given:
[D2 - 7DD' + 6D '2] z = xy
The auxiliary equation is
Example
1.5.13 : Solve [D2 + 3 DD' + 2D '2] z = x + y
Solution:
Given: [D2 + 3DD' + 2D 2]z = x+y
The auxiliary equation is
Example
1.5.14: Solve [D2 + 4DD' - 5D'2] z ] z = x + y2+л
Solution
:
Given : [D2 + 4DD' − 5D'2]z = x + y2+π
The auxiliary equation is
EXERCISES
Find
the particular Integral of
R.H.S = eax + by xr ys
Example
1.5.15 : Solve : [D2 - DD' - 6D'2] z = x2y + e3x+y.
Solution
:
Given : [D2 - DD' - 6D'2] z = x2y + e3x+y.
The auxiliary equation is
Example
1.5.16 : Solve (D2 + DD' - 6D2) z = x2y+e3x+y
Solution:
The auxiliary equation is m2+m-6 = 0
m = 2, -3
Example
1.5.17: Solve (D2 - 6DD' + 5D 2) z = ex sinh y
+ xy
Solution
: Given: [D2 – 6DD ' + 5D 2 ] = ex sinh y + xy
Example
1.5.18 : Solve (D2 + 2DD' + D'2) z = x2y+ ex-y
Solution
:
Transforms And Partial Differential Equations: UNIT I: Partial Differential Equations : Tag: : - Examples
Transforms and Partial Differential Equations
MA3351 3rd semester civil, Mechanical Dept | 2021 Regulation | 3rd Semester Mechanical Dept 2021 Regulation